https://leetcode-cn.com/problems/reverse-nodes-in-k-group/

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* reverseKGroup(ListNode* head, int k) {
if(k == 1) {
return head;
}
ListNode * top = head;
ListNode * ans;
ListNode * ed = head;

int cnt = 0;
int flag = 0;
while(head != nullptr) {
cnt++;
if(cnt == k) {
cnt = 0;
ListNode * tmp = head -> next;
ListNode * tmp3 = head -> next;
ListNode * tmp4 = top;
while(top != head) {
ListNode * tmp2 = top -> next;
top -> next = tmp;
tmp = top;
top = tmp2;
}
head -> next = tmp;
if(flag == 0) {
ans = head;
flag = 1;
}
else {
ed -> next = head;
}
ed = tmp4;
top = tmp3;
head = tmp3;
}
else
head = head -> next;
}
return ans;
}
};